复制代码 代码如下:  

rem dos get current time 

rem ======================= 

rem get yyyy/mm/dd 

set mydate=%DATE:~0,10% 

echo %mydate% 

rem ======================= 

rem get yyyy 

set yyyy=%DATE:~0,4% 

echo %yyyy% 

rem ======================= 

rem get mm 

set mm=%DATE:~5,2% 

echo %mm% 

rem ======================= 

rem get dd 

set dd=%DATE:~8,2% 

echo %dd% 

rem ======================= 

rem get yyyy-mm-dd 

set curdate=%yyyy%-%mm%-%dd% 

echo %curdate%

其实bat中获取时间就是利用截取日期字符串的方法

DOS下有字符处理的方法的，总结如下：

在这个日期格式下：”2013-07-22 星期一”， 这个%DATE:~0,10%得到的是2013-07-22
说明：DATE为系统变量，“:”表示开始处理前面的字符串“~0,10”表示从第0个字符开始取10个字符。


输出：

C:\Documents and Settings\Administrator>rem DOS get current time
C:\Documents and Settings\Administrator>rem =======================
C:\Documents and Settings\Administrator>rem get yyyy/mm/dd
C:\Documents and Settings\Administrator>set mydate=2013-07-22
C:\Documents and Settings\Administrator>echo 2013-07-22
2013-07-22
C:\Documents and Settings\Administrator>rem =======================
C:\Documents and Settings\Administrator>rem get yyyy
C:\Documents and Settings\Administrator>set yyyy=2013
C:\Documents and Settings\Administrator>echo 2013
2013
C:\Documents and Settings\Administrator>rem =======================
C:\Documents and Settings\Administrator>rem get mm
C:\Documents and Settings\Administrator>set mm=07
C:\Documents and Settings\Administrator>echo 07
07
C:\Documents and Settings\Administrator>rem =======================
C:\Documents and Settings\Administrator>rem get dd
C:\Documents and Settings\Administrator>set dd=22
C:\Documents and Settings\Administrator>echo 22
22
C:\Documents and Settings\Administrator>rem =======================
C:\Documents and Settings\Administrator>rem get yyyy-mm-dd
C:\Documents and Settings\Administrator>set curdate=2013  -07  -22
C:\Documents and Settings\Administrator>echo 2013  -07  -22
2013  -07  -22
C:\Documents and Settings\Administrator>

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